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y^2+11y-1452=0
a = 1; b = 11; c = -1452;
Δ = b2-4ac
Δ = 112-4·1·(-1452)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-77}{2*1}=\frac{-88}{2} =-44 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+77}{2*1}=\frac{66}{2} =33 $
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